5y^2+36y-1395=0

Solution for 5y^2+36y-1395=0 equation:

5y^2+36y-1395=0

a = 5; b = 36; c = -1395;
Δ = b2-4ac
Δ = 362-4·5·(-1395)
Δ = 29196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{29196}=\sqrt{36*811}=\sqrt{36}*\sqrt{811}=6\sqrt{811}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6\sqrt{811}}{2*5}=\frac{-36-6\sqrt{811}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6\sqrt{811}}{2*5}=\frac{-36+6\sqrt{811}}{10}
$